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Java: In Java, which comparison about Union-Find and Disjoint Set is accurate?

Difficulty:

Easy

Questions:

1

Time Limit:

2 minutes

Passing Score:

100%

Question

In Java, which comparison about Union-Find and Disjoint Set is accurate?

  1. It is much more efficient for repeated merge and connectivity checks than rebuilding components from scratch after each update.
  2. There is no practical difference in behavior, performance, or API design when Union-Find and Disjoint Set is involved.
  3. The oldest option related to Union-Find and Disjoint Set is always the right production choice regardless of context.
  4. Differences around Union-Find and Disjoint Set are mostly cosmetic, so correctness and maintainability do not change.

Hint

Focus on the behavior or tradeoff, not just the keyword.

Answer and rationale

Correct answer: A. It is much more efficient for repeated merge and connectivity checks than rebuilding components from scratch after each update.

It is much more efficient for repeated merge and connectivity checks than rebuilding components from scratch after each update. This is the comparison that usually separates memorization from understanding.

Track: Java